5

Sum of the elements of a table

  1. #include <stdio.h>
  2.  
  3. double sum( const float tab[], const unsigned siz ) {
  4.     double sum; /* same name! */
  5.     int i;
  6.  
  7.     for ( sum = 0.0, i = 0; i < siz; i++ )
  8.         sum += tab[ i ];
  9.     return sum;
  10. }
  11.  
  12. main() {
  13.     float f[] = { 1.0, 1.0/10, 1.0/100, 1.0/1000, 1.0/10000, 1.0/100000, 1.0/1000000 };
  14.  
  15.     printf( "sum=%f\n", sum( f, sizeof(f)/sizeof(float)) );
  16. }

Comments

Your comment:
[p] [b] [i] [u] [s] [quote] [pre] [br] [code] [url] [email] strip help 2000

Enter a maximum of 2000 characters.
Improve the presentation of your text with the following formatting tags:
[p]paragraph[/p], [b]bold[/b], [i]italics[/i], [u]underline[/u], [s]strike[/s], [quote]citation[/quote], [pre]as is[/pre], [br]line break,
[url]http://www.izend.org[/url], [url=http://www.izend.org]site[/url], [email]izend@izend.org[/email], [email=izend@izend.org]izend[/email],
[code]command[/code], [code=language]source code in c, java, php, html, javascript, xml, css, sql, bash, dos, make, etc.[/code].